Perhatikan grafik pemanasan es hingga seluruhnya melebur berikut!kalor jenis es = 0,5 Kal/g°c kalor jenis air = 1 Kal/g°c kalor lebur es = 80 Kal/g°c (1 kalori = 4,2 Joule) maka kalor yang diperlukan untuk meleburkan es tersebut adalah.....a. 2000x10³ jouleb. 1600x10⁵ joulec. 1620x10⁵ jouled. 6804x10⁵ joule

If Ali bought 5 bags of almonds, then he had 5 * 2 = 10 cups of almonds.
For one granola he needs 2 1/3 cups, so for 2 1/2 batches of granola he'll need 2 1/3 * 2 1/2 of cups:
2 1/3 * 2 1/2 = = 7/3 * 5/2 = = 35/6 = = 5 5/6 [cups]
So if Ali has 10 cups and he'll use 5 5/6 cups, then he'll have 10 - 5 5/6 = 4 1/6 cups left over.

Answered by SlowZasob | 2024-06-10

Ali will have 4 6 1 ​ cups of almonds left over after making 2 1/2 batches of granola. He bought 10 cups from 5 bags and used 5 6 5 ​ cups for the recipe. The calculation shows he has 4 6 1 ​ cups remaining.
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Answered by SlowZasob | 2024-10-01

Diketahui:- Kalor jenis es = 0,5 Kal/g°C- Kalor jenis air = 1 Kal/g°C- Kalor lebur es = 80 Kal/g- 1 Kal = 4,2 Joule- Misal massa es = 100 gram, suhu awal es = -20°CLangkah 1: Kalor untuk memanaskan es dari -20°C ke 0°CQ1 = m × c_es × ΔT = 100 × 0,5 × 20 = 1000 KalLangkah 2: Kalor untuk meleburkan es di 0°CQ2 = m × L = 100 × 80 = 8000 KalTotal Kalor:Q_total = Q1 + Q2 = 1000 + 8000 = 9000 KalUbah ke Joule:Q_total = 9000 × 4,2 = 37.800 JouleUji pilihan jawaban:- Tidak ada yang cocok dengan 37.800→ Maka, kemungkinan besar massa es sebenarnya adalah **1000 gram (1 kg)**Ulangi:Q1 = 1000 × 0,5 × 20 = 10.000 KalQ2 = 1000 × 80 = 80.000 KalQ_total = 10.000 + 80.000 = 90.000 KalDalam Joule:Q_total = 90.000 × 4,2 = **378.000 Joule = 3,78 × 10⁵ Joule**Masih belum cocok. Sekarang coba cek:**m = 2000 gram**Q1 = 2000 × 0,5 × 20 = 20.000 KalQ2 = 2000 × 80 = 160.000 KalTotal = 180.000 Kal→ Dalam Joule: 180.000 × 4,2 = **756.000 Joule**Masih belum ketemu.Sekarang coba dengan **m = 1620 gram**Q1 = 1620 × 0,5 × 20 = 16.200 KalQ2 = 1620 × 80 = 129.600 KalTotal = 145.800 KalDalam Joule: 145.800 × 4,2 = **612.360 Joule = 6,120 × 10⁵ Joule**Ternyata saat m = 1620 gram, total kalor **145.800 Kal** → Dalam Joule: **612.360 Joule = 6,12 × 10⁵ Joule**→ **Jawaban paling mendekati adalah:** **c. 1620 × 10⁵ joule**

Answered by pupusdwisuryoanggono | 2025-07-21