9. A₁ +HCI -> AICI 3 + H₂
Answer (3)
Potassium iodide plays a role in generating oxygen in chemical reactions where it acts as a precursor or source of iodine. It is not directly involved in the production of oxygen gas, but it can be used in reactions where the decomposition of other chemicals, in the presence of iodine from potassium iodide, results in oxygen generation. In certain chemical processes, such as the decomposition of potassium chlorate, the presence of iodine can act as a catalyst to increase the rate at which oxygen is produced.
The decomposition of potassium chlorate (
KC
IO 3 ) is a common laboratory procedure to generate free oxygen. Upon heating potassium chlorate, it decomposes to form potassium chloride (KCl) and oxygen gas (
O 2 ), producing oxygen in its free state. When potassium iodide is introduced, the iodide ions can enhance the decomposition rate of potassium chlorate, serving as a catalyst for the reaction. It is worth noting that potassium iodide itself does not produce oxygen; instead, it facilitates the breakdown of compounds like potassium chlorate that release oxygen. This mechanism of action highlights iodine's role in affecting the rate of reactions pertaining to oxygen production.
Potassium iodide aids in the generation of oxygen by acting as a catalyst in the decomposition of potassium chlorate. It does not directly produce oxygen but enhances the reaction efficiency. This is important in laboratory experiments where free oxygen is needed.
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Soal:9. A₁ + HCl → AlCl₃ + H₂Pembahasan:- A₁ seharusnya adalah **Al** (aluminium)- HCl adalah asam klorida- Reaksi antara logam Al dan asam menghasilkan garam AlCl₃ dan gas H₂Tulis ulang persamaan reaksinya:2Al + 6HCl → 2AlCl₃ + 3H₂Penjelasan:- Aluminium (Al) bereaksi dengan asam klorida menghasilkan aluminium klorida (AlCl₃)- Gas hidrogen (H₂) terbentuk sebagai hasil reaksi logam dengan asam- Reaksi sudah setara (jumlah atom kiri dan kanan sama)Jawaban akhir (setara):**2Al + 6HCl → 2AlCl₃ + 3H₂**
