VincenTragosta - Tanya, Jawab, dan Belajar Tanpa Batas Logo

In Wirausaha / Sekolah Menengah Atas | 2025-07-21

Di APO, proses POD (konfirmasi pesanan) untuk order grabmart dilakukan pada tab…

Asked by eriska3689

Answer (3)

Let Xb be the number of reservations that are accommodated. Xb has the binomial distribution with n trials and success probability p = 0.94
In general, if X has the binomial distribution with n trials and a success probability of p then P[Xb = x] = n!/(x!(n-x)!) * p^x * (1-p)^(n-x) for values of x = 0, 1, 2, ..., n P[Xb = x] = 0 for any other value of x.
To use the normal approximation to the binomial you must first validate that you have more than 10 expected successes and 10 expected failures. In other words, you need to have n * p > 10 and n * (1-p) > 10.
Some authors will say you only need 5 expected successes and 5 expected failures to use this approximation. If you are working towards the center of the distribution then this condition should be sufficient. However, the approximations in the tails of the distribution will be weaker espeically if the success probability is low or high. Using 10 expected successes and 10 expected failures is a more conservative approach but will allow for better approximations especially when p is small or p is large.
If Xb ~ Binomial(n, p) then we can approximate probabilities using the normal distribution where Xn is normal with mean μ = n * p, variance σ² = n * p * (1-p), and standard deviation σ
I have noted two different notations for the Normal distribution, one using the variance and one using the standard deviation. In most textbooks and in most of the literature, the parameters used to denote the Normal distribution are the mean and the variance. In most software programs, the standard notation is to use the mean and the standard deviation.
The probabilities are approximated using a continuity correction. We need to use a continuity correction because we are estimating discrete probabilities with a continuous distribution. The best way to make sure you use the correct continuity correction is to draw out a small histogram of the binomial distribution and shade in the values you need. The continuity correction accounts for the area of the boxes that would be missing or would be extra under the normal curve.
P( Xb < x) ≈ P( Xn < (x - 0.5) ) P( Xb > x) ≈ P( Xn > (x + 0.5) ) P( Xb ≤ x) ≈ P( Xn ≤ (x + 0.5) ) P( Xb ≥ x) ≈ P( Xn ≥ (x - 0.5) ) P( Xb = x) ≈ P( (x - 0.5) < Xn < (x + 0.5) ) P( a ≤ Xb ≤ b ) ≈ P( (a - 0.5) < Xn < (b + 0.5) ) P( a ≤ Xb < b ) ≈ P( (a - 0.5) < Xn < (b - 0.5) ) P( a < Xb ≤ b ) ≈ P( (a + 0.5) < Xn < (b + 0.5) ) P( a < Xb < b ) ≈ P( (a + 0.5) < Xn < (b - 0.5) )
In the work that follows X has the binomial distribution, Xn has the normal distribution and Z has the standard normal distribution.
Remember that for any normal random variable Xn, you can transform it into standard units via: Z = (Xn - μ ) / σ
In this question Xn ~ Normal(μ = 0.94 , σ = sqrt(0.94 * n * 0.06) )
Find n such that:
P(Xb ≤ 160) ≥ 0.95
approximate using the Normal distribution P(Xn ≤ 160.5) ≥ 0.95
P( Z ≤ (160.5 - 0.94 * n) / sqrt(0.94 * n * 0.06)) ≥ 0.95
P( Z < 1.96 ) ≥ 0.95
so solve this equation for n
(160.5 - 0.94 * n) / sqrt(0.94 * n * 0.06) = 1.96
n = 164.396
n must be integer valued so take the ceiling and you have:
n = 165.
The air line can sell 165 tickets for the flight and accommodate all reservates at least 95% of the time
If you can understand that...

Answered by Anonymous | 2024-06-10

To ensure a 95% probability of accommodating all reservation holders for a flight with a capacity of 160, the airline can accept a maximum of 165 reservations, given a no-show rate of 6%. This is determined using the binomial distribution and the normal approximation. Calculations reveal that with 165 reservations, the expected number of show-ups fits the airline's capacity requirement.
;

Answered by Anonymous | 2024-11-12

Jawaban:Di APO (Aplikasi Point of Order), proses POD (Proof of Delivery) atau konfirmasi pesanan untuk order GrabMart biasanya dilakukan pada tab “Pesanan Masuk” atau “Order Masuk”, tergantung versi aplikasinya.Penjelasan:Kalau di APO, proses POD (konfirmasi pesanan) buat orderan GrabMart biasanya ada di tab "Pesanan Masuk".Pas pesanan dari GrabMart udah selesai disiapin dan siap dikasih ke driver, kamu tinggal buka pesanan itu, terus lanjut ke bagian POD-nya buat konfirmasi. Biasanya isinya kayak:Scan QR dari driverAtau isi bukti kalau barang udah diterimaPokoknya, intinya POD ini buat buktiin kalau pesanan udah benar-benar diserahkan ke driver.Kadang nama tab-nya bisa beda dikit tergantung update aplikasinya, tapi umumnya sih tetap di bagian “Pesanan” atau “Order Masuk”.SEMOGA MEMBANTU!!

Answered by RAP121221 | 2025-08-04