x − am o u n t o f c an d y w hi c h cos t 5 , 45$ y − am o u n t o f c an d y w hi c h cos t 7 , 33$ 7 , 33 ∗ y + 11 ∗ 5 , 45 = 6 , 14 ( 11 + y ) 7 , 33 y + 59 , 95 = 67 , 54 + 6 , 14 y ∣ s u b t r a c t 6 , 14 y 1 , 19 y = 67 , 54 − 59 , 95 1 , 19 y = 7 , 59 ∣ d i v i d e b y 1 , 19 y = 6 , 38 p o u n d 6 , 38 p o u n d s s h o u l d b e mi x e d w i t h t h ose w i c h cos t 5 , 45.
The store needs to mix approximately 6.38 pounds of the $7.33 candy with 11 pounds of the $5.45 candy to sell the mixture at $6.14 per pound. This was determined by setting up an equation based on the total cost of the candies. Solving the equation revealed the necessary amount needed of the more expensive candy.
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Jawaban:kombinasi gerak lokomotor, non-lokomotor, dan manipulatifPenjelasan:1. Berlari → termasuk gerak lokomotor (karena tubuh berpindah tempat).2. Melompat → juga gerak lokomotor (karena masih melibatkan perpindahan tubuh).3. Menyundul bola → termasuk gerak manipulatif (karena berinteraksi dengan objek, yaitu bola).