6. Air sebanyak 500 ml dengan suhu 30°C dipanaskan sampai mendidih. Berapa kalor yang dibutuhkan dalam pemanasan tersebut jika diketahui kalor jenis air 4.200 J/Kg°C? a. 127 kJ b. 147 kJ C. 172 kJ d. 174 kJ

53.70 - 9.60 = 44.10. 44.10 / 2 = 22.05. Each friend paid (not including the tip) $22.05.

Answered by ZackFry | 2024-06-10

$22.05 ;

Answered by mariahgonzalezg7 | 2024-06-13

Each friend paid $22.05 for the meal, excluding the tip. This amount is calculated by subtracting the tip from the total cost and then dividing the remaining cost by two. So, Keith and Michelle both contributed evenly to the meal's expenses.
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Answered by Anonymous | 2024-12-09

Diketahui:- Volume air = 500 ml = 0.5 liter = 0.5 kg (karena massa air 1 liter = 1 kg)- Kalor jenis air (c) = 4.200 J/kg°C- Suhu awal = 30°C- Suhu akhir = 100°C (suhu mendidih)- Perubahan suhu (ΔT) = 100°C - 30°C = 70°CRumus yang digunakan:Q = m * c * ΔTLangkah-langkah perhitungan:1. Tentukan massa air: m = 0.5 kg2. Tentukan perubahan suhu: ΔT = 70°C3. Hitung kalor: Q = 0.5 * 4200 * 70 = 147.000 J4. Konversi ke kilojoule: 147.000 J = 147 kJJadi, kalor yang dibutuhkan untuk memanaskan air sebanyak 500 ml dari suhu 30°C hingga mendidih adalah 147 kJ.Jawaban: **b. 147 kJ**

Answered by pupusdwisuryoanggono | 2025-07-22