tentukan bilangan oksidasi atom s pada so2 jumlah bilangan oksidasi 2 × (biloks 0) +1 (biloks s) =02×(-2)+ biloks s= 0-4 + biloks s=0biloks s = +4​

First you would see the biggest common factor in between 540 and 600. Here is a trick: to know if you have a factor of 3, you add the numbers of that number, then see if it is dividable by 3. So for number 540: 5+4+0=9. 9/3=3. So 540/3= 180. and for 600: 6+0+0=6. 6/3=2. 600/3=200. Now u have 180/200. divide that by 10 and u get 18/20. and finally you divide that by 2 and you get 9/10. Now the numbers i divided 540/600 we 3, 10 and 2. Numbers 3 and two are prime factors cause u cant divide them anymore unless u get 1 or a decimal number but number 10 is not prime since you can divide that by 2 witch will give you 5. So the prime factors of 540/600 are 2, 2, 3 and 5. 9/10

Answered by Funcool | 2024-06-10

540∣2 270∣2 135∣5 . 27∣3 . 9∣3 . 3∣3 . 1∣ 540 = 2 × 2 × 5 × 3 × 3 × 3 600∣2 300∣2 150∣2 . 75∣3 . 25∣5 . 5∣5 . 1∣ 600 = 2 × 2 × 2 × 3 × 5 × 5
600 540 ​ = 2 × 2 × 2 × 3 × 5 × 5 2 × 2 × 5 × 3 × 3 × 3 ​ = 2 × 5 3 × 3 ​ = 10 9 ​

Answered by Anonymous | 2024-06-25

To reduce 600 540 ​ using prime factorization, we prime factor both numbers. The prime factorization gives us 10 9 ​ after canceling common factors. Therefore, the simplified form of the fraction is 10 9 ​ .
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Answered by Anonymous | 2024-10-01

Pertanyaan:Tentukan bilangan oksidasi atom S pada SO₂Jawaban:Unsur O (oksigen) biasanya punya bilangan oksidasi -2.Di SO₂ ada 2 atom O, jadi:2 × (-2) + biloks S = 0-4 + biloks S = 0Biloks S = +4Jadi, bilangan oksidasi atom S dalam SO₂ adalah +4.

Answered by sosokhytam1337 | 2025-07-27