gerakan melempar bola dari bawah menyerupai gerakan dalam olahraga​

l o g a ​ b + l o g a ​ c = l o g a ​ ( b ⋅ c ) l o g a ​ b − l o g a ​ c = l o g a ​ ( b : c ) l o g a ​ b c = c ⋅ l o g a ​ b
a ) l o g 2 + l o g 3 = l o g ( 2 ⋅ 3 ) = l o g 6 ​ b ) l o g 2 − l o g 3 = l o g ( 2 : 3 ) = l o g 3 2 ​ c ) 2 l o g 2 + l o g 3 = l o g 2 2 + l o g 3 = l o g 4 + l o g 3 = l o g ( 4 ⋅ 3 ) = l o g 12 d ) 2 l o g 2 − l o g 3 = l o g 2 2 − l o g 3 = l o g 4 − l o g 3 = l o g ( 4 : 3 ) = l o g 3 4 ​

Answered by Anonymous | 2024-06-10

Note: Log A + Log b = Log(A*B)
a) log 2 + log 3 = log (2*3) = log6.
Answer =a.

Answered by olemakpadu | 2024-06-10

The only option equal to lo g 6 is option A, which states lo g 2 + lo g 3 . This is because the property of logarithms allows us to express the sum of logarithms as the logarithm of a product. Thus, lo g 2 + lo g 3 = lo g ( 2 ⋅ 3 ) = lo g 6 .
;

Answered by Anonymous | 2024-09-05

Jawaban:Gerakan melempar bola dari bawah menyerupai gerakan dalam olahraga bowling atau underhand serve dalam olahraga bola voli.Kalau kamu maksudnya gerakan melempar bola dari bawah ke depan dengan ayunan tangan, itu biasanya disebut:Underhand throw (lemparan bawah)Underhand serve (pukulan bawah, khususnya di voli)Bowling action (gerakan melempar dalam bowling)

Answered by siiiiiiiiiiii | 2025-07-23