[y=3x^2+2x\ y=x(3x+2)\ y=x(x+\frac{2}{3})\ x=0 \vee x=-\frac{2}{3}\\ f(x)=5x^2-25x+30\ f(x)=5(x^2-5x+6)\ f(x)=5(x^2-2x-3x+6)\ f(x)=5(x(x-2)-3(x-2))\ f(x)=5(x-3)(x-2)\ x=3 \vee x=2
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To find the zeros of the function, we can rewrite it in intercept form. By factoring the function and setting the factors equal to zero, we determine the zeros, which in this example are x = 0 and x = -2/3. This method illustrates how to find the points where the graph intersects the x-axis.
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Jawaban:80 Penjelasan dengan langkah-langkah:Karena80+90+70= 240240÷3= 80tambahkan angka 80,90 dan 70 lali hasilnya dibagi dengan 3