tolong jawab kak mau di kumpulkan besok ​

Jawaban:Penjelasan:Diketahui:[tex]\overline F_1=F_1\angle \theta_1=10\text N\angle 30^{\circ}\\\overline F_2=F_2\angle \theta_2=40\text N\angle (-60^{\circ})[/tex]Ditanyakan:[tex]F_x, F_y=?[/tex]Alternatif penyelesaian:[tex]F_x=F_{1x}+F_{2x}\\F_x=F_1\cos \theta _1+F_2\cos \theta _2\\F_x=10\text N\cos 30^{\circ}+40\text N\cos( -60^{\circ})\\F_x=10\text N(\frac{1}{2}\sqrt{3} )+40\text N(\frac{1}{2} )\\F_x=5\sqrt{3} \,\text N+20\text N[/tex][tex]F_y=F_{1y}+F_{2y}\\F_y=F_1\sin \theta _1+F_2\sin \theta _2\\F_y=10\text N\sin 30^{\circ}+40\text N\sin (-60^{\circ})\\F_y=10\text N(\frac{1}{2} )-40\text N(\frac{1}{2} \sqrt{3} )\\F_y=5\text N-20\sqrt{3}\, \text N[/tex]Jadi resultan vektor ke arah sumbu x dan y berturut-turut adalah (5√3+20)N dan (5-20√3)N

Answered by mastreeada | 2025-08-04