vektor axb merupakan operasi cross product [tex]axb = \left[\begin{array}{ccc}i&j&k\\-5&-3&0\\0&4&2\end{array}\right] \\[/tex]axb = ((-3.2)-(4.0))i - ((-5.2)-(0.0)) j + ((-5.4)-(-3.0))k = ((-6)-(0))i - ((-10)-(0)) j + ((-20)-(0))k = -6i + 10j - 20kjadi axb = -6i+10j-20k