VincenTragosta - Tanya, Jawab, dan Belajar Tanpa Batas Logo

In Fisika / Sekolah Menengah Atas | 2025-08-11

tolong plzzz hehehehhehe​

Asked by viviika900

Answer (1)

Penyelesaian[tex]v_0 = 20 ~\text{m/s}[/tex][tex]h_0 = 25~ \text{m}[/tex][tex]g = 10 ~\text{m/s}^2[/tex][tex]y(t) = h_0 + v_0 t - \frac{1}{2} g t^2[/tex][tex]0 = 25 + (20) t - \frac{1}{2} (10) t^2[/tex][tex]0 = 25 + 20 t - 5 t^2[/tex][tex]-5 t^2 + 20 t + 25 = 0[/tex][tex]5 t^2 - 20 t - 25 = 0[/tex][tex]t^2 - 4 t - 5 = 0[/tex][tex]t = \frac{4 \pm \sqrt{(-4)^2 - 4(1)(-5)}}{2}[/tex][tex]= \frac{4 \pm \sqrt{16 + 20}}{2}[/tex][tex]= \frac{4 \pm \sqrt{36}}{2}[/tex][tex]= \frac{4 \pm 6}{2}[/tex][tex]= \frac{4 + 6}{2}[/tex]waktu dibutuhkan = [tex]\frac{10}{2} = 5 ~\text{s}[/tex]

Answered by vinganzbeut | 2025-08-11