2. 36°R = ....C ....F ....K3. 40°R = ....C ....F ....K4. 14°F = ....C ....R ....K​

2. 36°RC = (5/4) × 36 = 45°CF = (9/5) × 45 + 32 = 113°FK = 45 + 273 = 318KJawaban: 36°R = 45°C, 113°F, 318K3. 40°RC = (5/4) × 40 = 50°CF = (9/5) × 50 + 32 = 122°FK = 50 + 273 = 323KJawaban: 40°R = 50°C, 122°F, 323K4. 14°FC = (5/9) × (14 − 32) = −10°CR = (4/5) × (−10) = −8°RK = −10 + 273 = 263KJawaban: 14°F = −10°C, −8°R, 263K

Answered by dorotheaday7 | 2025-08-11