Penyelesaian[tex](a^4 \cdot b^{-3})^7[/tex][tex](x^m)^n = x^{m \cdot n}[/tex][tex](a^4)^7 = a^{4 \cdot 7} = a^{28}[/tex][tex](b^{-3})^7 = b^{-3 \cdot 7} = b^{-21}[/tex][tex](a^4 \cdot b^{-3})^7 = a^{28} \cdot b^{-21}[/tex][tex]=\frac{a^{28}}{b^{21}}[/tex]