pls butuh bantuan orang² pintar
Answer (1)
Jawaban: A. Soal Akar Kuadrat - a. 6√5 + 4√5 - 2√5- (6 + 4 - 2)√5 = 8√5- b. √72 - √18 + √50- √(362) - √(92) + √(25*2) = 6√2 - 3√2 + 5√2 = (6 - 3 + 5)√2 = 8√2- c. √54 - √24- √(96) - √(46) = 3√6 - 2√6 = √6- d. √12 + √27- √(43) + √(93) = 2√3 + 3√3 = 5√3- e. √50 + 5√32 - 3√13- √(252) + 5√(162) - 3√13 = 5√2 + 5*4√2 - 3√13 = 5√2 + 20√2 - 3√13 = 25√2 - 3√13 B. Soal Aljabar - a. (10a⁴y²) / (5a⁷y⁴)- (10/5) * (a⁴/a⁷) * (y²/y⁴) = 2 * a^(4-7) * y^(2-4) = 2 * a^(-3) * y^(-2) = 2 / (a³y²)- b. (-2n³y²7⁷) / (n⁻³y³7⁴)- -2 * (n³ / n⁻³) * (y² / y³) * (7⁷ / 7⁴) = -2 * n^(3-(-3)) * y^(2-3) * 7^(7-4) = -2 * n⁶ * y⁻¹ * 7³ = -2 * n⁶ * (1/y) * 343 = -686n⁶ / y- c. (156³c⁻¹) / (56c²)- (15/5) * (6³/6) * (c⁻¹ / c²) = 3 * 6^(3-1) * c^(-1-2) = 3 * 6² * c⁻³ = 3 * 36 * (1/c³) = 108 / c³ Ringkasan Jawaban: A. Soal Akar Kuadrat - a. 8√5- b. 8√2- c. √6- d. 5√3- e. 25√2 - 3√13 B. Soal Aljabar - a. 2 / (a³y²)- b. -686n⁶ / y- c. 108 / c³
