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In Matematika / Sekolah Menengah Pertama | 2025-08-19

kak bantuin kak (pake metode substitusi)​

Asked by shabynavisha

Answer (2)

Jawab:x + 2y = 10-2x + 3y = -6makax + 2y = 10x = 10 - 2y-2x + 3y = -6-2( 10 - 2y) + 3y = -6-20 + 4y + 3y = -64y + 3y = -6 + 207y = 14   y = 14/7   y = 2x + 2y = 10x + 2(2) = 10x + 4 = 10x = 10 -4x = 6HP = > x = 6 dan y = 2

Answered by agungkrishna79 | 2025-08-19

Penyelesaian[tex](x + 2y = 10)[/tex][tex](-2x + 3y = -6)[/tex][tex]x + 2y = 10[/tex][tex]x = 10 - 2y[/tex][tex]-2x + 3y = -6[/tex][tex]-2(10 - 2y) + 3y = -6[/tex][tex]-20 + 4y + 3y = -6[/tex][tex]-20 + 7y = -6[/tex][tex]7y = 14[/tex][tex]y = 2[/tex][tex]x = 10 - 2(2)[/tex][tex]= 10 - 4[/tex][tex]= 6[/tex][tex](x, y) = (6, 2)[/tex]

Answered by vinganzbeut | 2025-08-19