H ( x ) = ( x 2 ) + 1 an d K ( x ) = − ( x 2 ) + 4. K ( H ) = − ( H 2 ) + 4 = − ( x 2 + 1 ) 2 + 4 = 4 − ( x 2 + 1 ) 2 = . = 2 2 − ( x 2 + 1 ) 2 = ( 2 − x 2 − 1 ) ( 2 + x 2 + 1 ) = ( 1 − x 2 ) ( 3 + x 2 ) = . = ( 1 − x ) ( 1 + x ) ( x 2 − 3 ⋅ i 2 ) = ( 1 − x ) ( 1 + x ) ( x − 3 ⋅ i ) ( x + 3 ⋅ i ) K ( H ) = 0 ⇔ ( 1 − x ) ( 1 + x ) ( x − 3 ⋅ i ) ( x + 3 ⋅ i ) = 0 x = 1 or x = − 1 or x = 3 ⋅ i or x = − 3 ⋅ i A n s . e .
The roots of the equation K ( H ( x )) = 0 are ± 1 and ± i 3 . The correct answer is option E: ± 1 , ± i 3 .
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Jawaban: tentukan bilangan yang berada 9 satuan di atas -7. Soal: Naik 9 satuan dari -7 Penyelesaian: "Naik" berarti kita menambahkan. Jadi, kita perlu menambahkan 9 ke -7. -7 + 9 = 2 Kesimpulan: Naik 9 satuan dari -7 adalah 2.