f ( x ) = 2 1 ⋅ x + 3 f ( 0 ) = 2 1 ⋅ ( − 2 ) + 3 = − 1 + 3 = 2 f ( 0 ) = 2 1 ⋅ 0 + 3 = 0 + 3 = 3 f ( 2 ) = 2 1 ⋅ 2 + 3 = 1 + 3 = 4 T h e r an g e = { 2 ; 3 ; 4 }
The range of the function f ( x ) = 2 1 x + 3 for the domain { -2, 0, 2 } is { 2, 3, 4 }. We calculate the outputs for each input value step-by-step to determine this range.
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