x 2 + y 2 − 4 x − 6 y + 9 = 0 x 2 − 4 x + 16 + y 2 − 6 y + 9 − 16 = 0 ( x − 4 ) 2 + ( y − 3 ) 2 = 16 t hi s i s t h e e q u a t i o n o f a c i rc l e : ( x − a ) 2 + ( y − b ) 2 = r 2 ce n t er S = ( 4 ; 3 ) an d r a d i u s r = 4
By completing the square, the equation x 2 + y 2 − 4 x − 6 y + 9 = 0 is transformed into the standard form of a circle, ( x − 2 ) 2 + ( y − 3 ) 2 = 4 . The circle has its center at ( 2 , 3 ) and a radius of 2. This process involves rearranging and completing the square for both x and y .
;
Penyelesaian1. [tex](8x - 5y) - (4x - 6y)[/tex][tex]= (8x - 5y - 4x + 6y)[/tex][tex]= (8x - 4x) + (-5y + 6y)[/tex][tex]= 4x + y[/tex]2. [tex](4x - 3y) - (3x - 2y)[/tex][tex]= (4x - 3y - 3x + 2y)[/tex][tex]= (4x - 3x) + (-3y + 2y)[/tex][tex]= x - y[/tex]3.[tex](6x - 5y) - (4x - 3y)[/tex][tex]= (6x - 5y - 4x + 3y)[/tex][tex]= (6x - 4x) + (-5y + 3y)[/tex][tex]= 2x - 2y[/tex]