x³ + 6x² + 5x - 12
= x³ - x² + 7x² + 12x - 12
If we add all the coefficients, we get that the answer is 0. Thus, (x-1) is a factor of polynomial.
= x²(x-1) + 7x(x-1) + 12(x-1)
on re-arranging (x-1) as a common factor ;
= (x-1)(x²+7x+12) .........................................(1)
Now, we factorize (x² + 7x + 12)
(x² + 7x + 12)
= x² + 3x + 4x + 12 = x(x + 3) + 4(x + 3)
= (x + 4)( x +3) ..........................................(2)
On substituting for p(x) in 1 and 2, we get
(px) = (x-1)(x+4)(x+3)
x 3 + 6 x 2 + 5 x − 12 = x 3 − x 2 + 7 x 2 − 7 x + 12 x − 12 = = x 2 ( x − 1 ) + 7 x ( x − 1 ) + 12 ( x − 1 ) = ( x − 1 ) ( x 2 + 7 x + 12 ) = = ( x − 1 ) ( x 2 + 3 x + 4 x + 12 ) = ( x − 1 ) [ x ( x + 3 ) + 4 ( x + 3 )] = = ( x − 1 ) ( x + 3 ) ( x + 4 )
The expression P ( x ) = x 3 + 6 x 2 + 5 x − 12 is a cubic polynomial. Its highest degree is 3, with coefficients of 1, 6, 5 for each term respectively, and a constant term of -12. To find its roots, further methods may be needed, such as factoring or graphical analysis.
;
Jawaban:y=f(x) =2×y=f(x) =2×+1y=f(x) =2-×y=f(x) =2×+1