perbaiki kalimat berikut dengan huruf kafital!andi bermain bersama alan​

0 \Rightarrow"> p > 0 ⇒
2 p + 2 (even)
p 3 − p (odd or even)
p 2 + p (even)
p 2 − p (even)
7 p − 3 (ODD); 7p odd, 7p-3 = (odd)-(odd)=(odd)

Answered by turk3005 | 2024-06-10

0\\\\(A)\ \ \ 2p+2=2(p+1)\ \rightarrow\ \ even\ number\\\\(B)\ \ \ p^3-p=p(p^2-1)=p(p-1)(p+1)\ \rightarrow\ \ even\ number\\\\(C)\ \ \ p^2+p=p(p+1)\ \rightarrow\ \ even\ number\\\\(D)\ \ \ p^2-p=p(p-1)\ \rightarrow\ \ even\ number\\\\(E)\ \ \ 7p-3=6p-4+p+1=2(3p-2)+p+1\\\\p-odd\ \rightarrow\ \ (p+1)- even\ \rightarrow\ (7p-3)-even\ number\\\\p-even\ \rightarrow\ \ (p+1)- odd\ \rightarrow\ (7p-3)-odd\ number\\\\Ans.\ E"> p > 0 ( A ) 2 p + 2 = 2 ( p + 1 ) → e v e n n u mb er ( B ) p 3 − p = p ( p 2 − 1 ) = p ( p − 1 ) ( p + 1 ) → e v e n n u mb er ( C ) p 2 + p = p ( p + 1 ) → e v e n n u mb er ( D ) p 2 − p = p ( p − 1 ) → e v e n n u mb er ( E ) 7 p − 3 = 6 p − 4 + p + 1 = 2 ( 3 p − 2 ) + p + 1 p − o dd → ( p + 1 ) − e v e n → ( 7 p − 3 ) − e v e n n u mb er p − e v e n → ( p + 1 ) − o dd → ( 7 p − 3 ) − o dd n u mb er A n s . E

Answered by kate200468 | 2024-06-10

The expression that could be an odd integer when p is a positive integer is Option E: 7 p − 3 . This expression can yield odd results only when p is even. All other options produce even results regardless of whether p is odd or even.
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Answered by turk3005 | 2024-12-17

Jawaban:Andi bermain bersama Alan.

Answered by shisosalt | 2025-08-21