(x3 + x -312
Pakai
2
RIMUS
2
(a² + 2ab+ 2 ac + 2bc + b² + c²)
Answer (3)
"> a) \ \ \ f(x)= \frac{\big{5x-2}}{\big{x^2-5x+6}} \ \ \ \ \ \ \ \ \ D:\ \big{x^2-5x+6} \neq 0\\\\x^2-2x-3x+6 \neq 0\ \ \ \Leftrightarrow\ \ \ x(x-2)-3(x-2) \neq 0\\\\\Leftrightarrow\ \ \ (x-2)(x-3) \neq 0\ \ \ \Leftrightarrow\ \ \ x \neq 2\ \ \ and\ \ \ x \neq 3\\\\D=R-\{2;\ 3\}\\\\b) \ \ \ g(x)=\sqrt{5-2x} \ \ \ \ \ \ D:\ 5-2x \geq 0\ \ \ \Leftrightarrow\ \ \ -2x \geq -5\\\\\ \ \ \Leftrightarrow\ \ \ x \leq 2.5\ \ \ \Rightarrow\ \ \ D=(-\infty;2.5>
The domain of the function f ( x ) = x 2 − 5 x + 6 5 x − 2 is D = ( − ∞ , 2 ) ∪ ( 2 , 3 ) ∪ ( 3 , ∞ ) , and the domain of g ( x ) = 5 − 2 x is D = ( − ∞ , 2.5 ] .
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Jawaban:uraikan ekspresi (x³ + x - 3)² : 1. Identifikasi a, b, dan c:- a = x³- b = x- c = -32. Terapkan Rumus (a + b + c)² = a² + b² + c² + 2ab + 2ac + 2bc:(x³ + x - 3)² = (x³)² + (x)² + (-3)² + 2(x³)(x) + 2(x³)(-3) + 2(x)(-3)3. Sederhanakan:- (x³)² = x⁶- (x)² = x²- (-3)² = 9- 2(x³)(x) = 2x⁴- 2(x³)(-3) = -6x³- 2(x)(-3) = -6x4. Gabungkan Semua Suku:(x³ + x - 3)² = x⁶ + x² + 9 + 2x⁴ - 6x³ - 6x5. Susun Ulang (Opsional):Kita bisa susun ulang suku-suku agar pangkatnya menurun:(x³ + x - 3)² = x⁶ + 2x⁴ - 6x³ + x² - 6x + 9 Jadi, (x³ + x - 3)² = x⁶ + 2x⁴ - 6x³ + x² - 6x + 9
