27 2per3 kurang 8 1per3
Answer (3)
f ( x ) = x + 2 ; x 0 = 0 f ( x 0 ) = f ( 0 ) = 0 + 2 = 2 f ( x 1 ) = f ( 2 ) = 2 + 2 = 4 f ( x 2 ) = f ( 4 ) = 4 + 2 = 6 f ( x 3 ) = f ( 6 ) = 6 + 2 = 8
The first three iterates of the function F ( x ) = x + 2 starting from x 0 = 0 are x 1 = 2 , x 2 = 4 , and x 3 = 6 .
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Jawab:= 27 2/3 - 8 1/3 = 83/3 - 25/3= 58/3= 19 1/3
