For the **angle **AOB = 4x - 2 and BOC = 5x + 10 and COD = 2x + 14, the value of x is 14.36
We have to given that;
Angle AOB = 4x - 2
And, ∠ BOC = 5x + 10
And, ∠ COD = 2x + 14.
By given condition we get;
∠AOB + ∠BOC + ∠COA = 180
4x - 2 + 5x + 10 + 2x +14 = 180
9x + 8 + 2x + 14 = 180
11x + 22 = 180
11x = 180 - 22
11x = 158
Now **divide **11 from both sides;
x = 14.36
Therefore, If angle AOB = 4x - 2 and BOC = 5x + 10 and COD = 2x + 14. the value of x is 1.
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To solve for x, we need to set up and solve the equations given. We have m<AOB = 4x-2, m<BOC = 5x+10, and m<COD = 2x+14. To solve for x, we can set up the equation: 4x-2 + 5x+10 + 2x+14 = 180 (since the sum of all angles in a triangle is 180 degrees). Simplifying this equation gives us 11x + 22 = 180. Subtracting 22 from both sides gives us 11x = 158, and dividing by 11 gives us x = 14. Therefore, the value of x is 14.
To solve for x , we set up the equation ( 4 x − 2 ) + ( 5 x + 10 ) + ( 2 x + 14 ) = 180 , leading to x = 14.36 . This value can then be used to determine the actual measures of the angles. Finally, we confirm the value is accurate by isolating and solving for x .
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