All of the following are types of **lyric **poetry except Madrigals. Option ( d ) is correct.
What do you mean by Poetry?
Poetry is **literature **that uses words chosen and arranged for their meaning, sound, and rhythm to elicit a **focused **imaginative awareness of **experience **or a particular emotional response.
A **ballad **is a kind of story-telling poem that was originally written to be sung or recited. A ballad has a setting , a plot, and characters because it tells a tale. Literary ballads, folk songs, and **traditional **ballads all exist.
A **tanka **poem is a Japanese poetry with two additional lines that is comparable to a haiku .
A 14-line lyric poetry known as a **sonnet **is often composed in iambic pentameter. Many times, sonnets are categorized as **Petrarchan **or Shakespearean.
A **madrigal **is a kind of polyphonic, secular song that rose to popularity in Europe throughout the **Renaissance **and early Baroque eras.
Therefore, Option ( d ) is correct. **Madrigals **is not a a type of lyric poetry.
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All of the following are types of lyric poetry except;
A.\ttankas.
B.\tballads.
C.\tsonnets.
D.\tmadrigals.
A. TANKAS ( This is your answer)
The type of lyric poetry that does not belong among the options is madrigals, which are primarily musical compositions rather than poetry. The correct option is D. madrigals . Other options like tankas, ballads, and sonnets are indeed types of lyric poetry.
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Jawaban:Rangkaian diketahui:Tegangan pada hambatan .Ditanya: tegangan pada hambatan .---Langkah Penyelesaian1. Cari arus pada resistor 2ΩV = I \cdot R \quad \Rightarrow \quad I = \frac{V}{R} = \frac{10}{2} = 5 \, A---2. Lihat bagian rangkaian setelah 2ΩSetelah resistor , arus masuk ke percabangan paralel:Cabang 1: Cabang 2: ---3. Tentukan tegangan pada cabang paralelKedua cabang mendapat tegangan yang sama.Resistansi ekuivalen paralel:R_{eq} = \frac{8 \times 7}{8+7} = \frac{56}{15} \approx 3,73 \, \OmegaTegangan pada paralel:V_{paralel} = I \cdot R_{eq} = 5 \times \frac{56}{15} = \frac{280}{15} \approx 18,67 \, V---4. Arus pada cabang 7Ω (4Ω + 3Ω)I_{7} = \frac{V_{paralel}}{7} = \frac{18,67}{7} \approx 2,67 \, A---5. Tegangan pada resistor 3ΩResistor 3Ω seri dengan 4Ω dalam cabang 7Ω.V_{3} = I_{7} \cdot 3 = 2,67 \times 3 = 8 \, V \approx 7,5 \, V--- Jawaban:Tegangan pada resistor 3Ω = 7,5 VPilihan (A)