f or e a c h α ∈ R ( f or e x am pl e α = 2 x ) t h e ma x o f y = s in α i s 1 an d t h e min o f y = s in α i s − 1 t h e am pl i t u d e o f y = s in α i s 1 − ( − 1 ) = 2 t h e n t h e am pl i t u d e o f y = 2 1 s in 2 x i s 2 1 ⋅ 2 = 1
( − 2 1 , 2 1 ) Amplitutde: ( 2 1 − ( − 2 1 )) = 1 Normally for sinx amplitude is 2 (1 +1). In the case when it is half sine amplitude is halved, therefore 0.5 +0.5 = 1 Paramers alpha = 2x does not matter because it only stretches the graph horizontally.
The amplitude of the function y = 2 1 sin ( 2 x ) is 2 1 , which means the wave oscillates between − 2 1 and + 2 1 . The coefficient 2 1 in front of sine determines the amplitude. The parameter 2 x affects the wave's frequency but not the amplitude.
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Jawaban:Kalimat Langsung → Kalimat Tidak LangsungDia mengatakan bahwa baju yang dia pakai adalah hadiah ulang tahunnya Kalimat Tidak Langsung → Kalimat Langsung "Rapikan meja belajar sebelum tidur." Suruh AyahMaaf kalau salah kak