Let the number be y. 7 times the number means 7y. therefore, 6 more than 7y is 41 means 6 + 7y = 41. Further simplification : 6 + 7y = 41 7y = 41 - 6 = 35 y = 35/7 = 5
First you have to give the number a name. Call it Bob.
6 more than 7 times Bob is 41.
(7 Bob) + 6 = 41
The algebraic equation for "6 more than 7 times a number is 41" is 7 x + 6 = 41 . This is done by defining a variable for the number, expressing the terms mathematically, and then setting them equal to 41. The final equation is a clear representation of the original statement.
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Penyelesaian[tex]f(x) = 4x^2 - 26x + 32[/tex][tex]f(1) = 4(1^2) - 26(1) + 32[/tex][tex]= 4(1) - 26 + 32[/tex][tex]= 4 - 26 + 32[/tex][tex]= (4 + 32) - 26[/tex][tex]= 36 - 26[/tex][tex]= 10[/tex]