SPLDV dengan menggunakan metode substitusi 2×+3y=7 dan 2×+y=3​

T h e f i rs t j ug : v in e g a r o i l ​ = 1 3 ​ ⇒ t h e v o l u m e o f t h e o i l = 4 3 ​ o f t h e j ug . ⇒ t h e v o l u m e o f o i l = 4 3 ​ l i t re T h e seco n d j ug : v in e g a r o i l ​ = 1 4 ​ ⇒ t h e v o l u m e o f t h e o i l = 5 4 ​ o f t h e j ug . ⇒ t h e v o l u m e o f o i l = 5 4 ​ l i t re
T h e l a r g er j ug : 4 3 ​ l i t re + 5 4 ​ l i t re = 0.75 + 0.8 [ l i t re ] = 1.55 [ l i t re ] A n s . t h e v o l u m e o f t h e o i l i s 1.55 l i t res .

Answered by kate200468 | 2024-06-10

I n t h e f i rs t j ug i s 4 3 ​ l o l i v e o i l . I n t h e seco n d j ug i s 5 4 ​ l o l i v e o i l 4 3 ​ l + 5 4 ​ l 4 3 ​ → t h e d e n o mina t or i s 4 l i s t t h e m u lt i pl es o f 4 : 0 ; 4 ; 8 ; 12 ; 16 ; 20 ​ ; 24 ; 28 ; ... 5 4 ​ → t h e d e n o mina t or i s 5 l i s t t h e m u lt i pl es o f 5 : 0 ; 5 ; 10 ; 15 ; 20 ​ ; 25 ; 30 ; ... L e a s t C amm o n De n o mina t or o f 4 3 ​ an d 5 4 ​ i s 20
4 3 ​ = 4 ⋅ 5 3 ⋅ 5 ​ = 20 15 ​ 5 4 ​ = 5 ⋅ 4 4 ⋅ 4 ​ = 20 16 ​ − − − − − − − − − − − − − − − − − 4 3 ​ l + 5 4 ​ l = 20 15 ​ l + 20 16 ​ l = 20 15 + 16 ​ l = 20 31 ​ l = 1 20 11 ​ l = 1.55 l ← so l u t i o n

Answered by Anonymous | 2024-06-10

The total volume of oil in the larger jug is 1.55 liters, calculated by adding 0.75 liters from the first jug and 0.8 liters from the second jug.
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Answered by kate200468 | 2024-12-24

Jawaban:2x + 3y = 72x + y = 3---------------- - 2y = 4 y = 2 2x + 2 = 32x = 1x = 1/2

Answered by gtesting880 | 2025-08-22

Penyelesaian[tex]2x + 3y = 7 \quad(1)[/tex][tex]2x + y = 3\quad(2)[/tex][tex]2x + y = 3[/tex][tex]y = 3 - 2x[/tex][tex]2x + 3(3 - 2x) = 7[/tex][tex]2x + 9 - 6x = 7[/tex][tex]-4x + 9 = 7[/tex][tex]-4x = -2[/tex][tex]x = \tfrac{1}{2}[/tex][tex]y = 3 - 2\left(\tfrac{1}{2}\right)[/tex][tex]y = 3 - 1[/tex][tex]y = 2[/tex][tex]x = \tfrac{1}{2}, y = 2[/tex]

Answered by vinganzbeut | 2025-08-22