to solve these problems we can solve by substitution or elimination method. Now we use the method of elimination.
The first equation : q - 2r = 4
second equation : q + r = 37
now elimination equations 1 and 2 q − 2 r = 4 q + r = 37 − − 3 r = − 33 r = − 3 − 33 r = 11 so the value of r is 11
now find the value of q by inserting r into equation 1 q − 2 r = 4 q − 2 ( 11 ) = 4 q − 22 = 4 q = 4 + 22 q = 26
**so the value of q is 26 **
**So the value of : ****r = 11 ** q = 26
q-2r=4, therefore: q=4+2r.
Plug the value of q into q+r=37, so you get:
4+2r+r=37
3r=37-4=33
3r=33
Therefore: r=11.
q-2r=4, but r=11, so:
q-2(11)=4
q-22=4
Therefore q=26.
Check if the answer is correct using second equation:
q=4+2r=4+2(11)=4+22=26.
So: q=26 and r=11.
To solve the given system of equations, we found that r = 11 and q = 26 . We used the substitution method, first expressing q in terms of r and substituting it into the first equation. This allowed us to solve for r and subsequently find q .
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