Sebuah benda diletakkan didepan lensa yang berjarak 20cm. Jika bayangan yang terbentuk berjarak 30cm, berapakah jarak fokusnya? ​

the answer is 9/ 24 because 9/24 = 0.375 and 3/8 = 0.375 . both of the fraction equals the same value.

Answered by kab423 | 2024-06-10

Answer:
9/24
Step-by-step explanation:

Answered by andrew0745 | 2024-06-12

The fraction equivalent to 8 3 ​ is 24 9 ​ . This was determined by simplifying each option and finding that option B matches 8 3 ​ .
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Answered by andrew0745 | 2024-10-02

Jawaban:- Diketahui:- Jarak benda (s) = 20 cm- Jarak bayangan (s') = 30 cm- Ditanya:- Jarak fokus lensa (f) = ?- Solusi:Rumus lensa:1/f = 1/s + 1/s'Substitusikan nilai s dan s':1/f = 1/20 + 1/30Samakan penyebut (KPK dari 20 dan 30 adalah 60):1/f = 3/60 + 2/601/f = 5/601/f = 1/12Maka:f = 12 cm Jadi, jarak fokus lensa tersebut adalah 12 cm.

Answered by ara1412 | 2025-08-22