8. Pak Eka memanen cabai di kebun seberat 3,42 kg. Di hari yang sama, Pak Yogi juga memanen cabai seberat 3,61 kg. Siapa yang memanen cabai lebih berat, Pak Eko atau Pak Yogi?​

Let us take logarithms on both sides. 200 log n < 300 log 5 So log n < 3/2 log 5 log n < log 5 power 3/2 n < 5 power 3/2 n < square root (5³) = √125
so n = 11

Answered by Everest2017 | 2024-06-10

n 200 < 5 300 ( n 2 ) 100 < ( 5 3 ) 100 ⇒ n 2 < 5 3 ⇒ n 2 < 125 ∈ I ⇒ n < 125 ​ an d 125 ​ = 5 5 ​ ≈ 11.18 A n s . t h e l a r g es t in t e g er n i s 11

Answered by kate200468 | 2024-06-24

The largest integer n such that n 200 < 5 300 is 11, derived by manipulating and simplifying the inequality. This is determined by taking the 200th root of both sides and evaluating that result. Hence, n < 11.18 , and the maximum integer value is 11.
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Answered by kate200468 | 2024-12-24

Jawaban:pak Yogi memanen cabai lebih banyak dari pak eko

Answered by adiseftiawantian | 2025-08-22