Ukara ngoko ngendhog

w − t h e w i d t h l = w + 5 − t h e l e n g t h T h e p er im e t er o f rec t an g l e : P = 58 c m P = 2 w + 2 l 2 w + 2 ( w + 5 ) = 58 2 w + 2 w + 10 = 58 4 w + 10 = 58 ∣ s u b t r a c t 10 f ro m b o t h s i d es 4 w = 48 ∣ d i v i d e b o t h s i d es b y 4 w = 12 ( c m ) l = 12 + 5 = 17 ( c m ) A n s w er : T h e d im e n s i o n s o f t h e rec t an g l e : 17 c m × 12 c m

Answered by Anonymous | 2024-06-10

hey i believe that you have to multiply those to numbers

Answered by cailyn19 | 2024-06-10

The dimensions of the rectangle are a width of 12 cm and a length of 17 cm. The length is 5 cm greater than the width, satisfying the given conditions. The perimeter of the rectangle is 58 cm.
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Answered by Anonymous | 2024-12-18

Jawaban:Penjelasan:Nggendog kalebu tembung andhahan kang kadadeyan saka tembung lingga endog kang diwenehi ater-ater ng-Conto:Pitikku wis ngendog sepuluh.Nggendog iku tembung ngoko. Krama madya lan krama inggil ngendog yaiku nigan kang uga kalebu tembung andhahan kedadeyan saka tembung lingga tigan kang diimbuhi ater-ater n-Conto:Ayam kula sampun nigan sedasa.

Answered by mastreeada | 2025-08-23