bahasa krama sebelum berangkat sekolah​

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Answered by Anonymous | 2024-06-10

3(x - 8) - 5 = 9(x + 2) + 1
First, you have to get rid of the parentheses:
3(x - 8) is the same as 3x - 24, so the left side is 3x - 29 .
9(x + 2) is the same as 9x + 18, so the right side is **9x + 19 **.
Now, the equation is: ** 3x - 29 = 9x + 19**
Subtract 19 from each side: 3x - 48 = 9x
Subtract 3x from each side: - 48 = 6x
Divide each side by 6 : - 8 = x
(I guess the answer is not 7.166 after all.)

Answered by AL2006 | 2024-06-10

The solution to the equation is x = − 8 . We achieved this by isolating x through distribution, combining like terms, and simplifying. A check of the solution confirms that both sides of the original equation are equal when x is substituted back in.
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Answered by Anonymous | 2024-12-24

RIYIN/SEDURUNG BIDHAL SEKOLAH (sebelum berangkat sekolah )Penjelasan:•MEMINTA IZIN"Pak/Bu, kula nyuwun pamit badhe tindak sekolah." (Ayah/Ibu, saya mohon izin akan pergi ke sekolah.)"Kula badhe kesah sak mangke." (Saya akan berangkat nanti.)•KEMOHON RESTU "Nuwun pangestu." (Mohon restu.)"Mugi-mugi pinaringan lancar ing sedaya giat." (Semoga diberikan kelancaran dalam semua kegiatan.)•KESELURUHAN "Pak/Bu, kula nyuwun pamit badhe tindak sekolah. Nuwun pangestu." (Ayah/Ibu, saya mohon izin akan pergi ke sekolah. Mohon restunya.)

Answered by ayysukagolz27 | 2025-08-23