Potensial listrik pada titik A dan pada titik E berturut-turut adalah 20 V dan 30 V, potensial listrik pada titik B, C, dan D secara berurutan adalah
Answer (3)
Arrange ratio: If the dog ate 12 muffins and this accounted for three-tenths of total how many muffins is a whole? Therefore, our ratio is as follows:
where 1 is a whole, and 3/10 = 0.3
12 ----------- 0.3 x ------------- 1
Multiply on the cross:
12 * 1 = 0.3 * x 0.3x = 12 |:0,3 x = 40
There are 40 muffins.
You started with a total of 40 muffins. This is determined by the fact that 12 eaten muffins represent 10 3 of the total. Therefore, by solving 10 3 ⋅ x = 12 , we find x = 40 .
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Jawaban:Diketahui:- Potensial di titik A (VA) = 20 V- Potensial di titik E (VE) = 30 V- Arus dan resistansi:- A ke P: Arus (IAP) = 4A, Resistansi (RAP) = 4 ohm- E ke Q: Arus (IEQ) = 3A, Resistansi (REQ) = 6 ohm- Q ke D: Arus (IQD) = 2A, Resistansi (RQD) = 8 ohm- P ke B: Resistansi (RPB) = 3 ohm- Q ke C: Resistansi (RQC) = 5 ohm- P ke Q: Resistansi (RPQ) = 2 ohm Ditanya:- Potensial di titik B (VB)- Potensial di titik C (VC)- Potensial di titik D (VD)Caranya=1. Potensial di Titik P:- VA - VP = IAP * RAP- 20 - VP = 4 * 4- 20 - VP = 16- VP = 20 - 16 = 4 V2. Potensial di Titik Q:- VE - VQ = IEQ × REQ- 30 - VQ = 3 ÷ 6- 30 - VQ = 18- VQ = 30 - 18 = 12 V3. Arus dari P ke Q (IPQ):- VP - VQ = IPQ × RPQ- 4 - 12 = IPQ × 2- -8 = IPQ × 2- IPQ = -4 A (berarti arus dari Q ke P adalah 4A)4. Arus dari P ke B (IPB):- Arus masuk P = Arus keluar P- IAP = IPQ + IPB- 4 = -4 + IPB- IPB = 8 A5. Potensial di Titik B:- VP - VB = IPB × RPB- 4 - VB = 8 × 3- 4 - VB = 24- VB = 4 - 24 = -20 V6. Arus dari Q ke C (IQC):- Arus masuk Q = Arus keluar Q- IEQ + IPQ = IQC + IQD- 3 + 4 = IQC + 2- IQC = 7 - 2 = 5 A7. Potensial di Titik C:- VQ - VC = IQC × RQC- 12 - VC = 5 × 5- 12 - VC = 25- VC = 12 - 25 = -13 V8. Potensial di Titik D:- VQ - VD = IQD × RQD- 12 - VD = 2 × 8- 12 - VD = 16- VD = 12 - 16 = -4 V Kesimpulan:- Potensial di titik B (VB) = -20 V- Potensial di titik C (VC) = -13 V- Potensial di titik D (VD) = -4 V
