Polinomial P(x) dibagi (x - 2) bersisa 6 dan jika dibagi (x - 1) bersisa -13. Tentukan sisa pembagian P(x) oleh x² - 3x + 2!

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Answered by taskmasters | 2024-06-10

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Answered by jinglesahu65 | 2024-06-24

Geographers study human systems and human-environment relationships to understand human activity, analyze environmental impacts, forecast trends, support policy development, and consider cultural contexts. This knowledge is vital for creating sustainable practices and making informed decisions. By examining these relationships, they can contribute significantly to addressing global challenges and promoting human welfare.
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Answered by taskmasters | 2024-12-26

Jawaban:kita selesaikan soal sisa pembagian polinomial menggunakan konsep Teorema Sisa.Diketahui:P(x) dibagi (x−2) bersisa 6 → P(2) = 6P(x) dibagi (x−1) bersisa −13 → P(1) = −13Kita diminta menentukan sisa saat dibagi x²−3x+2.Perhatikan bahwa x²−3x+2 = (x−1)(x−2). Jadi sisa pembagian P(x) oleh x²−3x+2 adalah polinomial linear: R(x) = ax + b.Substitusi ke nilai x yang membuat faktor nol:1. x = 1 → a + b = −132. x = 2 → 2a + b = 6Selisih:(2a + b) − (a + b) = 6 − (−13) → a = 19Kemudian a + b = −13 → 19 + b = −13 → b = −32Jadi sisa pembagian: R(x) = 19x − 32✅ Jawaban: 19x − 32Penjelasan dengan langkah-langkah:Udah segitu dulu jawaban dariku semoga bermanfaat… jangan lupa dijadiin jawaban tercerdas yaaa

Answered by kheisyaalv | 2025-08-24

Jawaban:Diketahui: - *P(x) ÷ (x - 2)* sisa *6*, artinya *P(2) = 6* - *P(x) ÷ (x - 1)* sisa *–13*, artinya *P(1) = –13* - Ditanya: *Sisa pembagian P(x) oleh (x² - 3x + 2)*Perhatikan: *x² - 3x + 2 = (x - 1)(x - 2)* → Karena derajat pembagi = 2, maka *sisa pembagian adalah polinomial berderajat kurang dari 2*, yaitu: *S(x) = ax + b*---Misal: P(x) = (x² - 3x + 2)·Q(x) + ax + bSubstitusi x = 2: P(2) = a(2) + b = 6 → 2a + b = 6 → (1) Substitusi x = 1: P(1) = a(1) + b = –13 → a + b = –13 → (2)Kurangkan (1) – (2): (2a + b) – (a + b) = 6 – (–13) a = 19Substitusi ke (2): 19 + b = –13 → b = –32---Jawaban:*Sisa pembagian = 19x – 32

Answered by edyrianto2000 | 2025-08-24