tentukan bentuk sederhana dari oprasi penjumlahan dan pengurangan bentuk akar berikut! A. 8√5-4√5+2√20 B. 4√2+3√8-5√16D. 4√96+3√24-4√54 tolong cari kakk beserta langka langka nyaa(sebenarnya masih ada satu cuma salah tulis, mungkin kakak kakak yang sudah belajar ini tolong cari kan yang C dia sama seperti itu kalo saya tulis mungkin kalian gak ngerti tolong kakakk kakak)
Answer (4)
You don't usually have a choice of whether the decimal is terminating. Once they give you the numbers to divide, the decimal is either terminating or else it isn't.
In this case, it is.
27/120 = 0.225
basting average usually has thee figure after the decimal:
AVG = 27/120 = 0.225
The terminating decimal for 27 hits in 120 at-bats is 0.225. This result is obtained by dividing 27 by 120. The decimal terminates, meaning it does not continue infinitely.
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SOAL A.[tex]8 \sqrt{5} - 4 \sqrt{5} + 2 \sqrt{20} [/tex][tex]= 8 \sqrt{5} - 4 \sqrt{5} + 2 \sqrt{4 \times 5} [/tex][tex]= 8 \sqrt{5} - 4 \sqrt{5} + 2 \times 2 \sqrt{5} [/tex][tex]= 8 \sqrt{5} - 4 \sqrt{5} + 4 \sqrt{5} [/tex][tex]= (8 - 4 + 4) \sqrt{5} [/tex][tex]= 8 \sqrt{5} [/tex]SOAL B.[tex]4 \sqrt{2} + 3 \sqrt{8} - 5 \sqrt{16} [/tex][tex]= 4 \sqrt{2} + 3 \sqrt{4 \times 2} - 5 \times 4[/tex][tex]= 4 \sqrt{2} + 3 \times 2 \sqrt{2} - 20[/tex][tex]= 4 \sqrt{2} + 6 \sqrt{2} - 20[/tex][tex]= (4 + 6) \sqrt{2} - 20[/tex][tex]= 10 \sqrt{2} - 20[/tex]SOAL D.[tex]4 \sqrt{96} + 3 \sqrt{24} - 4 \sqrt{54} [/tex][tex]= 4 \sqrt{16 \times 6} + 3 \sqrt{4 \times 6} - 4 \sqrt{9 \times 6} [/tex][tex]= 4 \times 4 \sqrt{6} + 3 \times 2 \sqrt{6} - 4 \times 3 \sqrt{6} [/tex][tex]= 16 \sqrt{6} + 6 \sqrt{6} - 12 \sqrt{6} [/tex][tex]= (16 + 6 - 12) \sqrt{6} [/tex][tex]= 10 \sqrt{6} [/tex]
