Diketahui tiga garis 2×-y=0,4×-y-5=0,dan a×-y-7=0 melalui satu titi.nilai a adalah
Answer (4)
**9x - 7y = -7
- 7y = -9x -7 Divide both sides by - 7, we get
y = 9 /7 x + 1 Answer**
Slope Intercept Form: y = m x + b
9 x − 7 y = − 7 − 7 y = − 9 x − 7 y = 7 9 x + 1
The equation 9 x − 7 y = − 7 can be transformed into slope-intercept form by isolating y . The final form is y = 7 9 x + 1 , where the slope m = 7 9 and the y-intercept b = 1 .
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Jawaban:beserta caranya1. Cari titik potong dua garis pertama:- Garis 1: 2x - y = 0 --> y = 2x- Garis 2: 4x - y - 5 = 0- Substitusi y = 2x ke persamaan garis 2: 4x - 2x - 5 = 0- 2x = 5- x = 5/2- y = 2 × (5/2) = 5- Titik potong: (5/2, 5)2. Substitusi titik potong ke garis ketiga:- Garis 3: ax - y - 7 = 0- Substitusi x = 5/2 dan y = 5: a(5/2) - 5 - 7 = 0- (5/2)a = 12- a = 12 × (2/5) = 24/5 maka, nilai a yaitu 24/5.
