Saha wae tokoh nu aya dina dongeng sasakala rengit di sada dina ceuli

f ( x ) + g ( x ) = x 3 + 2 x 2 + 3 x 2 − 1 = x 3 + 5 x 2 − 1 D : x ∈ R
f ( x ) − g ( x ) = x 3 + 2 x 2 − ( 3 x 2 − 1 ) = x 3 + 2 x 2 − 3 x 2 + 1 = x 3 − x 2 + 1 D : x ∈ R
f ( x ) \cdotg ( x ) = ( x 3 + 2 x 2 ) ( 3 x 2 − 1 ) = 3 x 5 − x 3 + 6 x 4 − 2 x 2 = 3 x 5 + 6 x 4 − x 3 − 2 x 2 D : x ∈ R
g ( x ) f ( x ) ​ = 3 x 2 − 1 x 3 + 2 x 2 ​ 3 x 2 − 1  = 0 3 x 2  = 1 x 2  = 3 1 ​ x  = − 3 3 ​ ​ ∧ x  = 3 3 ​ ​ D : x ∈ ( − ∞ , − 3 3 ​ ​ ) ∪ ( 3 3 ​ ​ , ∞ )

Answered by konrad509 | 2024-06-10

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Answered by Anonymous | 2024-06-10

We found the following for the functions: f + g = x 3 + 5 x 2 − 1 , f − g = x 3 − x 2 + 1 , f ⋅ g = 3 x 5 + 6 x 4 − x 3 − 2 x 2 , and g f ​ = 3 x 2 − 1 x 3 + 2 x 2 ​ with respective domains. The domains for addition, subtraction, and multiplication are all real numbers, while the domain for division excludes values where the denominator is zero. Overall, handling polynomial operations requires considering the domain restrictions primarily in division cases.
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Answered by konrad509 | 2024-12-24