Tentukan biloks unsur yang digarisbawahi pada zat-zat berikut ini a. MN O4-b. p o4 ³-c. k2 cr2 o7d. fe2 (so4) 3​

In the first number, I think you mean commas instead of periods. I hope that's right.
Let me see if I can line up all the pieces correctly on the screen:
114,000,000,000 70,000 8,000 7
Now, by carefully implementing the mathematical operation called "addummup", you arrive at the conclusion, which is just the sum of the pieces:
**114,000,078,007 ** .

Answered by AL2006 | 2024-06-10

the standard form is: 114,000,078,007

Answered by biya | 2024-06-10

The sum of 114,000,000,000 + 70,000 + 8,000 + 7 equals 114,000,078,007. This number in standard form is expressed as 1.14 × 10¹¹. Scientific notation simplifies large numbers for easier handling and communication.
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Answered by AL2006 | 2024-12-24

Jawaban:soal:Tentukan bilangan oksidasi (biloks) unsur yang digaris bawahi pada zat-zat berikut ini:a. MnO₄⁻b. PO₄³⁻c. K₂Cr₂O₇d. Fe₂(SO₄)₃caranya:a. MnO₄⁻:* Oksigen (O) memiliki biloks -2.* Total biloks O dalam MnO₄⁻ = 4 × (-2) = -8* Total biloks ion = -1* Biloks Mn + (-8) = -1* Biloks Mn = +7b. PO₄³⁻:* Oksigen (O) memiliki biloks -2.* Total biloks O dalam PO₄³⁻ = 4 × (-2) = -8* Total biloks ion = -3* Biloks P + (-8) = -3* Biloks P = +5c. K₂Cr₂O₇:* Kalium (K) memiliki biloks +1.* Oksigen (O) memiliki biloks -2.* Total biloks K dalam K₂Cr₂O₇ = 2 × (+1) = +2* Total biloks O dalam K₂Cr₂O₇ = 7 × (-2) = -14* Total biloks senyawa = 0* (+2) + 2 × Biloks Cr + (-14) = 0* 2 * Biloks Cr = +12* Biloks Cr = +6d. Fe₂(SO₄)₃:* Ion sulfat (SO₄) memiliki biloks -2.* Total biloks (SO₄) dalam Fe₂(SO₄)₃ = 3 × (-2) = -6* Total biloks senyawa = 0* 2 × Biloks Fe + (-6) = 0* 2 × Biloks Fe = +6* Biloks Fe = +3 maka, bilangan oksidasinya yàitu:a. Mn = +7b. P = +5c. Cr = +6d. Fe = +3

Answered by ara1412 | 2025-08-24