kerjakan soak berikut: no 1-5 & 9,10​

50% gray 50% ebony genotype a are as follows: Gg, Gg, gg, and gg

Answered by Ari18Wolf | 2024-06-10

Answer:
The correct answer would be 1 (Gg) : 1 (gg).
The genotype of a heterozygous gray female would be Gg.
It will produce two types of gametes G and g.
The genotype of an ebony male would be homozygous gg as ebony is a recessive trait.
It will produce only one type of gamete that is, g.
The cross would produce offspring with the two types of genotype Gg and gg in the ratio 1:1.

Answered by JoiePatel | 2024-06-12

The genotypic ratio of the offspring from a heterozygous gray female (Gg) and an ebony male (gg) is 1:1, resulting in one gray-bodied genotype (Gg) and one ebony-bodied genotype (gg).
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Answered by JoiePatel | 2024-10-31

Jawaban:hasil transformasi geometri :1. Rotasi 180° di O (0,0): A(4,2) → A'(-4,-2)2. Rotasi -45° di O (0,0): B(-2,5) → B'(-√2/2 - 5√2/2, √2/2 - 5√2/2)3. Rotasi 120° di O (0,0): C(-1,6) → C'(3√3/2 - 1/2, -√3/2 - 3/2)4. Rotasi 60° di P (2,4): D(4,-5) → D'(6.5 - 4√3, 5 + √3)5. Rotasi -90° di Q (-2,1): E(5,6) → E'(-5, 4)6. Dilatasi faktor 3 di O (0,0): F(-3,-2) → F'(-9, -6)7. Dilatasi faktor 1/2 di O (0,0): G(8,-6) → G'(4, -3)8. Dilatasi faktor 2 di O (0,0): H(-3,10) → H'(-6, 20)9. Dilatasi faktor 4 di S (3,4): I(4,9) → I'(7, 24)10. Dilatasi faktor 1/3 di T (1,-2): J(5,-8) → J'(5/3, -4)Penjelasan dengan langkah-langkah:Penjelasan:- Rotasi: Menggunakan matriks rotasi untuk setiap sudut dan pusat yang sesuai.- Dilatasi: Mengalikan koordinat dengan faktor skala, dengan mempertimbangkan pusat dilatasi jika bukan di (0,0). Rumus yang digunakan:- Rotasi dengan pusat (0,0):- x' = x cos θ - y sin θ- y' = x sin θ + y cos θ- Rotasi dengan pusat (a,b):- x' = (x - a) cos θ - (y - b) sin θ + a- y' = (x - a) sin θ + (y - b) cos θ + b- Dilatasi dengan pusat (0,0):- x' = kk- y' = kk- Dilatasi dengan pusat (a,b):- x' = k(x - a) + a- y' = k(y - b) + bSemoga ini membantu

Answered by ara1412 | 2025-08-24