r 2 = r 1 − r + 3 1 ; D : r = 0 ∧ r = − 3 r 2 − r 1 = r + 3 − 1 r 1 = r + 3 − 1 cross m u lt i pl y r + 3 = − r r + r = − 3 2 r = − 3 r = − 1.5
r 2 = r 1 − r 1 + 3 an d r = 0 r 2 = 3 / ⋅ r 2 = 3 r / : 3 3 2 = r
We solved the equation 2 r = r 1 − r + 3 1 by eliminating the fractions and rearranging it into polynomial form. After solving the polynomial 2 r 3 + 6 r 2 − 3 = 0 , we found that one solution is r = − 1.5 .
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Penjelasan dengan langkah-langkah:Tentu, mari kita hitung: 3/10 * 5/12 = (3 * 5) / (10 * 12) = 15/120 Sekarang kita sederhanakan pecahan ini: 15/120 = (15 ÷ 15) / (120 ÷ 15) = 1/8 Jadi, tiga per sepuluh dikali lima per dua belas adalah 1/8.maaf kalo salahsemangat yah belajar nya