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Tussock moths obtain energy by cellular resporation by the oxidation of food they consume. The food they consume is oxidised to synthesize special type of phosphate which is then stored as energy. The energy is utilised by their cells whenever needed.
Tussock moths gain energy through cellular respiration by consuming carbohydrates and utilizing oxygen, resulting in the release of energy and production of carbon dioxide and water.
Tussock moths, like other organisms, obtain energy in cellular respiration through the breakdown of carbohydrate molecules. These moths are heterotrophs, which means they obtain their energy by consuming other organisms - primarily plants or plant-based materials that provide them with the necessary carbohydrates. During cellular respiration, these carbohydrate molecules react with oxygen to produce carbon dioxide and water, releasing energy stored in the chemical bonds of the food. This energy is then captured in the form of adenosine triphosphate (ATP), which is used by cells to carry out various vital functions.
Tussock moths obtain energy through cellular respiration by breaking down carbohydrates from their plant-based diet into glucose, which is then processed in mitochondria to produce ATP. This metabolic process involves glycolysis, the Krebs cycle, and the electron transport chain, ultimately leading to the release of energy and byproducts like carbon dioxide and water. The captured energy in ATP is essential for their cellular functions.
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Jawaban:Tentu, mari kita selesaikan soal-soal pada gambar tersebut dengan lebih ringkas. 1. Soal nomor 5: 32\frac{1}{5} + 64\frac{2}{3} - 125\frac{1}{3} \times 36\frac{1}{2} \div 8\frac{2}{3}Ubah menjadi pecahan:32\frac{1}{5} = \frac{161}{5}, 64\frac{2}{3} = \frac{194}{3}, 125\frac{1}{3} = \frac{376}{3}, 36\frac{1}{2} = \frac{73}{2}, 8\frac{2}{3} = \frac{26}{3}Substitusi dan hitung:\frac{161}{5} + \frac{194}{3} - \frac{376}{3} \times \frac{73}{2} \div \frac{26}{3} = \frac{161}{5} + \frac{194}{3} - \frac{376}{3} \times \frac{73}{2} \times \frac{3}{26} = \frac{161}{5} + \frac{194}{3} - \frac{13724}{26} = \frac{161}{5} + \frac{194}{3} - \frac{6862}{13} = \frac{1453}{15} - \frac{6862}{13} = \frac{-84041}{195} 2. Soal nomor 6: \frac{61\frac{5}{8} + 81\frac{1}{2}}{125\frac{2}{5} - 32\frac{2}{5}}Ubah menjadi pecahan:61\frac{5}{8} = \frac{493}{8}, 81\frac{1}{2} = \frac{163}{2}, 125\frac{2}{5} = \frac{627}{5}, 32\frac{2}{5} = \frac{162}{5}Substitusi dan hitung:\frac{\frac{493}{8} + \frac{163}{2}}{\frac{627}{5} - \frac{162}{5}} = \frac{\frac{493}{8} + \frac{652}{8}}{\frac{465}{5}} = \frac{\frac{1145}{8}}{93} = \frac{1145}{8 \times 93} = \frac{1145}{744} 3. Soal nomor 7: Hasil dari rasionalisasi - Opsi a) \frac{2}{\sqrt{6} + \sqrt{2}} = \frac{2(\sqrt{6} - \sqrt{2})}{(\sqrt{6} + \sqrt{2})(\sqrt{6} - \sqrt{2})} = \frac{2(\sqrt{6} - \sqrt{2})}{6 - 2} = \frac{2(\sqrt{6} - \sqrt{2})}{4} = \frac{\sqrt{6} - \sqrt{2}}{2}- Opsi b) \frac{3 + \sqrt{2}}{\sqrt{5} + \sqrt{3}} = \frac{(3 + \sqrt{2})(\sqrt{5} - \sqrt{3})}{(\sqrt{5} + \sqrt{3})(\sqrt{5} - \sqrt{3})} = \frac{(3 + \sqrt{2})(\sqrt{5} - \sqrt{3})}{5 - 3} = \frac{3\sqrt{5} - 3\sqrt{3} + \sqrt{10} - \sqrt{6}}{2}- Opsi c) \frac{\sqrt{8}}{6} = \frac{2\sqrt{2}}{6} = \frac{\sqrt{2}}{3}- Opsi d) \frac{\sqrt{8} + \sqrt{6}}{\sqrt{6}} = \frac{\sqrt{8}}{\sqrt{6}} + \frac{\sqrt{6}}{\sqrt{6}} = \sqrt{\frac{8}{6}} + 1 = \sqrt{\frac{4}{3}} + 1 = \frac{2}{\sqrt{3}} + 1 = \frac{2\sqrt{3}}{3} + 1 = \frac{2\sqrt{3} + 3}{3}
