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3 y + 4 x < 12 3 y < − 4 x + 12 / : 3 y < − 3 4 ​ x + 4

Answered by Lilith | 2024-06-10

To find a point on the boundary line of the inequality 3 y + 4 x < 12 , we set the equation to 3 y + 4 x = 12 and solve for y . This gives us the boundary line y = − 3 4 ​ x + 4 . Examples of points on this line include (0, 4) and (3, 0).
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Answered by Lilith | 2024-10-02

Jawaban:32^(1/5) + 64^(2/3) - 125^(1/3) × 36^(1/2) : 8^(2/3) caranya=1. Hitung setiap suku:- 32^(1/5) = 2 (karena 2^5 = 32)- 64^(2/3) = (akar pangkat 3 dari 64)^2 = 4^2 = 16- 125^(1/3) = 5 (karena 5^3 = 125)- 36^(1/2) = 6 (karena 6^2 = 36)- 8^(2/3) = (akar pangkat 3 dari 8)^2 = 2^2 = 42. Substitusi:2 + 16 - 5 × 6 : 43. Perkalian dan Pembagian:- 5 × 6 = 30- 30 : 4 = 7.54. Penjumlahan dan Pengurangan:2 + 16 - 7.5 = 18 - 7.5 = 10.5Jawaban: 10.5

Answered by ara1412 | 2025-08-25