Tolong bantu makasih

Just to add a couple of remarks to Konrad509's answer.
Yes, one of the right answers is: わたしはじゅうさいです。 [watashi ha juu-sai desu.]
In kanji it looks like this: 私は十歳です。 or 私は十才です。
If you wanted to customize your sentence a little bit then I would suggest changing the first person pronoun to something else. Therefore, if you're a girl, you might to use あたし [atashi] instead of わたし (私) [watashi]; if you're a teenage boy who wants to sound cool on the other hand, you might want to use おれ (俺) [ore].
Also you might want to add よ [yo] at the end of the whole sentence to sound more amiably.
I hope that it clears everything up for you. If you had more questions, you can just write to me personally ;)
Cheers!

Answered by Qba | 2024-06-10

In Japanese, "I am 10 years old" is written as わたしはじゅうさいです in hiragana. This structure features the pronoun for "I", the number for ten, and the phrase for "years old". You can customize the pronoun used depending on your gender or preference.
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Answered by Qba | 2024-12-24

Jawaban:Soal 20: Jika x = 64 dan y = 81, maka nilai dari (x^(2/3) + y^(-1/4)) / (x^(1/2) - y^(1/2)) = ?1. Hitung setiap suku:- x^(2/3) = 64^(2/3) = (akar pangkat 3 dari 64)^2 = 4^2 = 16- y^(-1/4) = 81^(-1/4) = 1 / (81^(1/4)) = 1 / (akar pangkat 4 dari 81) = 1/3- x^(1/2) = 64^(1/2) = akar kuadrat dari 64 = 8- y^(1/2) = 81^(1/2) = akar kuadrat dari 81 = 92. Substitusi:- (16 + 1/3) / (8 - 9) = (48/3 + 1/3) / (-1) = (49/3) / (-1) = -49/33. Ubah menjadi pecahan campuran:- -49/3 = -16 1/3 Jawaban Soal 20: A. -16 1/3Soal 26: Nilai dari ((125)^(2/3) - (81)^(1/4)) / ((8)^(2/3) + (25)^(1/2)) = ?1. Hitung setiap suku:- (125)^(2/3) = (akar pangkat 3 dari 125)^2 = 5^2 = 25- (81)^(1/4) = akar pangkat 4 dari 81 = 3- (8)^(2/3) = (akar pangkat 3 dari 8)^2 = 2^2 = 4- (25)^(1/2) = akar kuadrat dari 25 = 52. Substitusi:- (25 - 3) / (4 + 5) = 22 / 93. Sederhanakan:- 22/9 = 2 + 4/9 + 4/9 =2 4/9 Jawaban Soal no 26: Tidak ada jawaban yang sesuai dengan caranya, seharusnya 22/9=2 4/9

Answered by ara1412 | 2025-08-25