The resistance of a piece of wire is directly proportional to its length, so we know that just like the length, the resistance of each segment is also twice the resistance of the previous ('earlier') segment.
So the resistances of the segments are:
4
8 16 32
and their total resistance before they were cut up was
(4 + 8 + 16 + 32) = 60 ohms
The original wire, cut into 4 segments with resistances of 4 ohms, 8 ohms, 16 ohms, and 32 ohms, has a total resistance of 60 ohms. Each segment's resistance doubles the previous segment’s due to their lengths. Thus, the overall resistance of the original wire is 60 ohms.
;
Jawaban: A.Five Fifteenpenjelasan:Dilihat dari gambar maka:jarum panjang ke 3=15jarum pendek ke 5Jadi Five fifteen/05:15 o'clock