Dik. f(x) = (2x + 5) g(x) = (6x² - 5x + 3) h(x) = (5x³ - 2x² + 4x - 6)Dit. 1. h(x) + g(x)2. h(x) - g(x)3. f(x) . h(x)4. g(x) . h(x)5. f(x) . g(x)Note: #jangan copas dari ai, ataupun apk lain seperti Qanda#no ngasal
Answer (3)
The amount spent on postage will be 580.
How to calculate the value?
Let P = postage
Let s = supplies
p = s - 870 ,... i
The second equation will be:
2s = 5p .....
Substitute the values
2s = 5p
2s = 5(s - 870)
2s = 5s - 4350
5s - 2s = 4350
3s = 4350.
s = 4350/3
s = 1450
The amount spent on postage will be:
= 1450 - 870
= 580
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Acme Inc. spent $580 on postage. Using the defined equations based on the given information, we determined the amounts spent on both supplies and postage. The postage amount is found by substituting the supply amount into the equation relating them.
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Penyelesaian1. [tex]h(x) + g(x) = (5x^3 - 2x^2 + 4x - 6) + (6x^2 - 5x + 3)[/tex][tex]= 5x^3 + (-2x^2 + 6x^2) + (4x - 5x) + (-6 + 3)[/tex][tex]= 5x^3 + 4x^2 - x - 3[/tex]2.[tex]h(x) - g(x) = (5x^3 - 2x^2 + 4x - 6) - (6x^2 - 5x + 3)[/tex][tex]= 5x^3 + (-2x^2 - 6x^2) + (4x + 5x) + (-6 - 3)[/tex][tex]= 5x^3 - 8x^2 + 9x - 9[/tex]3.[tex](2x + 5)(5x^3 - 2x^2 + 4x - 6)[/tex][tex]= (2x)(5x^3 - 2x^2 + 4x - 6) + 5(5x^3 - 2x^2 + 4x - 6)[/tex][tex]= (10x^4 - 4x^3 + 8x^2 - 12x) + (25x^3 - 10x^2 + 20x - 30)[/tex][tex]= 10x^4 + ( -4x^3 + 25x^3 ) + (8x^2 - 10x^2) + ( -12x + 20x ) -30[/tex][tex]= 10x^4 + 21x^3 - 2x^2 + 8x - 30[/tex]4. [tex](6x^2 - 5x + 3)(5x^3 - 2x^2 + 4x - 6)[/tex][tex]6x^2(5x^3 - 2x^2 + 4x - 6) = 30x^5 - 12x^4 + 24x^3 - 36x^2[/tex][tex](-5x)(5x^3 - 2x^2 + 4x - 6) = -25x^4 + 10x^3 - 20x^2 + 30x[/tex][tex]3(5x^3 - 2x^2 + 4x - 6) = 15x^3 - 6x^2 + 12x - 18[/tex][tex]=30x^5 + (-12x^4 -25x^4) + (24x^3 + 10x^3 + 15x^3) + (-36x^2 -20x^2 -6x^2) + (30x + 12x) - 18[/tex][tex]= 30x^5 - 37x^4 + 49x^3 - 62x^2 + 42x - 18[/tex]5. [tex](2x + 5)(6x^2 - 5x + 3)[/tex][tex]= (2x)(6x^2 - 5x + 3) + 5(6x^2 - 5x + 3)[/tex][tex]= (12x^3 - 10x^2 + 6x) + (30x^2 - 25x + 15)[/tex][tex]= 12x^3 + 20x^2 - 19x + 15[/tex]
