70. Penyelesaian dari persamaan eksponen 10 x-² = x+³√10⁶ adalah.... A. {2,3} B. {4,3} C. (-2, 3} D. { -2, 1 } E. { -4, 3 }
Answer (3)
a 1 = 200 ; a 2 = 196 ; a 3 = 192 r = a 2 − a 1 → r = 126 − 200 = − 4 a n = a 1 + ( n − 1 ) r a n = 200 + ( n − 1 ) ⋅ ( − 4 ) = 200 − 4 n + 4 = 204 − 4 n a 14 = 204 − 4 ⋅ 14 = 204 − 56 = 148 A n s w er : A
The 14th term of the arithmetic sequence is 148. This is calculated using the formula for finding the n-th term of an arithmetic sequence, given the first term and the common difference. Therefore, the correct answer is A.
;
Jawaban:soal:Mencari penyelesaian persamaan eksponen 10^(x-2) = (x+3)√(10⁶). caranya:1. Ubah bentuk akar:- (x+3)√(10⁶) = (10⁶)^(1/(x+3)) = 10^(6/(x+3))2. Persamaan menjadi:- 10^(x-2) = 10^(6/(x+3))3. Karena basis sama (10), maka pangkatnya harus sama:- x - 2 = 6 / (x + 3)4. Kalikan kedua sisi dengan (x + 3):- (x - 2)(x + 3) = 65. Jabarkan dan sederhanakan:- x² + 3x - 2x - 6 = 6- x² + x - 12 = 06. Faktorkan persamaan kuadrat:- (x + 4)(x - 3) = 07. Cari nilai x:- x + 4 = 0 atau x - 3 = 0- x = -4 atau x = 3 Jawaban:E. { -4, 3 }
