Pada suatu bidang datar, terdapat segitiga ABC dengan AB = 6 cm, BC = 8 cm, dan AC = 10 cm. Pada bidang datar tersebut terdapat titik D yang berjarak 8 cm dari garis AB dan 6 cm dari garis BC. Jarak terjauh yang mungkin antara titik D dan garis AC adalah.... (A) 4,8 cm (B) 9,6 cm (C) 14,4 cm (D) 19,2 cm
Answer (4)
They really didn't hide it just kept it a secret, the Germans did know an invasion plan was at work just didn't know when or where it was going to happen. So they were ready on the beaches and planted land mines on the ground just in case, so if we came some soldiers would get blown up. The Nazi's were trying as hard as possible to get the info but it was to late by the time they got the news we had already taken over the french beach that they had doubt that was the beach we were going to land on.
Allies strategy was to convince axis that the invasion will take place in Pas de Calais. General Patton was commanding First United States Army Group - a fake army which was located on the other end of La Manche channel than Pas de Calais. Even after landing in Normandy Germans left toops in Calais, thinking that D Day landing is just a deception. It is known as Operation Quicksilver, part of Operation Fortitude.
The Allies hid their D-Day invasion plan from the Germans through misinformation campaigns, including misleading them about the invasion's location, particularly using Operation Fortitude. They also utilized poor weather conditions to their advantage and conducted airborne operations to disrupt German defenses. These strategies were effective in achieving surprise during the invasion on June 6, 1944.
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Jawaban:1. Periksa Jenis Segitiga- AB = 6 cm, BC = 8 cm, AC = 10 cm- Karena 6² + 8² = 36 + 64 = 100 = 10², maka segitiga ABC adalah segitiga siku-siku di B.2. Koordinat Titik Karena ini segitiga siku-siku di B, mari kita letakkan di bidang koordinat: - B(0, 0)- A(6, 0)- C(0, 8)Jadi, persamaan garis AC adalah:- y = mx + c- 8 = m(0) + c => c = 8- 0 = m(6) + 8 => m = -8/6 = -4/3- y = -4/3 x + 8- 4x + 3y - 24 = 0 3. Titik D- Jarak D ke AB (y = 0) adalah 8 cm- Jarak D ke BC (x = 0) adalah 6 cm- Ada 4 kemungkinan posisi D:- D1(6, 8)- D2(-6, 8)- D3(6, -8)- D4(-6, -8)4. Jarak Titik ke GarisJarak titik (x₁, y₁) ke garis Ax + By + C = 0 adalah:- d = |Ax₁ + By₁ + C| / √(A² + B²)Dalam kasus ini, garis AC adalah 4x + 3y - 24 = 0. Jadi A=4, B=3, C=-24 dan √(A² + B²) = √(16 + 9) = 55. Hitung Jarak untuk Setiap Titik D - D1(6, 8):- d = |4(6) + 3(8) - 24| / 5 = |24 + 24 - 24| / 5 = 24/5 = 4,8 cm- D2(-6, 8):- d = |4(-6) + 3(8) - 24| / 5 = |-24 + 24 - 24| / 5 = 24/5 = 4,8 cm- D3(6, -8):- d = |4(6) + 3(-8) - 24| / 5 = |24 - 24 - 24| / 5 = 24/5 = 4,8 cm- D4(-6, -8):- d = |4(-6) + 3(-8) - 24| / 5 = |-24 - 24 - 24| / 5 = |-72| / 5 = 72/5 = 14,4 cm 6. Jarak TerjauhJarak terjauh adalah 14,4 cm. - Jawaban: (C) 14,4 cm
