If the imaginary surface necessary to apply C-40-8 Law is called:
A. Cartesian Statute
B. Bipolar Surface
C. Gaussian Surface
D. None of the above
If the surface under consideration is not perpendicular to the field lines, then the expression for:
What is the integral form of the expression [tex]$2+1,1 cos e =
\frac{?}{s_0}$[/tex]
A. [tex]$\int x-a x=\frac{!!}{6!}$[/tex]
B. [tex]$\int K \cdot(-\frac{9}{8} C \cdot \int d \cdot d K=\frac{9}{6}$[/tex]
C. [tex]$\int h / 4=\frac{1}{4}$[/tex]
The expression for current density flowing through a conductor is represented by:
A. phil
B. posted
C. shill
D. enl
A 10 m length of copper wire has a diameter of 1 mm. Find the current density if it carries a current of 1.2 A.
A. [tex]$8.7807 \times 10^{\circ}- m ^2$[/tex]
B. [tex]$0.7897 \times 108 Alm ^2$[/tex]
C. [tex]$6.7897 \times 10^4 A / m ^2$[/tex]
D. [tex]$6.7891 \times 10 %$[/tex]
Which of the following expressions is not a representation of Ohm's law?
A. [tex]$\frac{U 2}{C A}$[/tex]
B. [tex]$\frac{14}{A}$[/tex]
C. [tex]$|\rho|$[/tex]
D. pH
The null deflection of a Potentiometer refers to:
A. When the galvanometer attached to the jockey deflects to the left
B. When the galvanometer attached to the jockey deflects to the right
C. When the galvanometer attached to the jockey rotates through 180 degrees
D. When the potential across the galvanometer cancels out
Answer (1)
Gaussian surface is necessary to apply C-40-8 Law.
Electric flux is calculated considering the angle between field and surface.
Current density is calculated as 1.527 × 1 0 6 A / m 2 .
pH is not a representation of Ohm's law.
Null deflection in a potentiometer occurs when the potential across the galvanometer cancels out.
Explanation
Introduction Let's address each question step-by-step, applying our knowledge of electromagnetism and circuit theory.
Question 10 - Gaussian Surface Question 10: The imaginary surface necessary to apply a law similar to Gauss's Law (referred to as C-40-8 Law in the question, which seems to be a typo or specific reference not widely known) is the Gaussian surface. Gauss's Law relates the electric flux through a closed surface to the charge enclosed by that surface.
Question 11 - Electric Flux Question 11: If the surface is not perpendicular to the field lines, the flux is given by the dot product of the electric field vector and the area vector: Φ = ∫ E ⋅ d A . This accounts for the angle between the field and the surface normal.
Question 12 - Integral Form Question 12: The question is incomplete and lacks context. However, if we assume the expression relates to Gauss's law, the integral form would involve integrating the electric field over a closed surface to relate it to the enclosed charge. Without more information, it's impossible to determine the correct integral.
Question 13 - Current Density Question 13: The expression for current density (J) flowing through a conductor is given by J = A I , where I is the current and A is the area. None of the options (phil, posted is shill, enl) seem to be standard notations or correct representations.
Question 14 - Calculating Current Density Question 14: We calculated the current density for a copper wire with a diameter of 1 mm carrying a current of 1.2 A. The current density is approximately 1.527 × 1 0 6 A / m 2 .
Question 15 - Ohm's Law Question 15: Ohm's law can be expressed as V = I R , where V is voltage, I is current, and R is resistance. Resistance can also be expressed as R = ρ A L , where ρ is resistivity, L is length, and A is area. The options A, B, and C can be related to Ohm's law. Option D, pH, is not a representation of Ohm's law.
Question 16 - Potentiometer Null Deflection Question 16: The null deflection of a potentiometer refers to when the potential across the galvanometer cancels out, resulting in zero current flow through the galvanometer.
Final Answers Based on the analysis above, here are the answers to the multiple-choice questions:
C. Gaussian surface
(Insufficient information to answer definitively)
(Insufficient information to answer definitively)
(None of the above)
The closest answer is A. 8.7807 × 1 0 ∘ − m 2 (Note: There seems to be a typo in the exponent. The correct order of magnitude should be 1 0 6 )
D. pH
D. When the potential across the galvanometer cancel out
Examples
Understanding these concepts is crucial in various real-world applications. For instance, calculating current density helps engineers design electrical wires and components that can safely handle specific currents without overheating. Similarly, understanding potentiometer principles is essential in designing accurate measurement circuits for sensors and other electronic devices. These principles form the foundation for designing efficient and safe electrical systems.
