To solve the equation 2 ( 4 − 3 x ) + 5 ( 2 x − 3 ) = 20 − 5 x , we need to follow these steps:
Distribute the constants in the equation:
For 2 ( 4 − 3 x ) , distribute 2: 2 × 4 − 2 × 3 x = 8 − 6 x .
For 5 ( 2 x − 3 ) , distribute 5: 5 × 2 x − 5 × 3 = 10 x − 15.
Substitute the results back into the equation: 8 − 6 x + 10 x − 15 = 20 − 5 x .
Combine like terms on the left side of the equation:
Combine − 6 x and 10 x :
− 6 x + 10 x = 4 x .
Combine 8 and − 15 :
8 − 15 = − 7. So the equation becomes: 4 x − 7 = 20 − 5 x .
Add 5 x to both sides to move all x terms to one side of the equation: 4 x + 5 x − 7 = 20. 9 x − 7 = 20.
Add 7 to both sides to solve for x : 9 x = 20 + 7. 9 x = 27.
Divide both sides by 9 to isolate x : x = 9 27 . x = 3.
Thus, the solution to the equation is x = 3 .
The correct option is (\text{D}), x = 3."}