Q1. Think and fill two 3-digit numbers such that their sum gives a 3-digit number. Addition must involve carryover. + 3-digit number 3-digit number 3-digit number Think and fill two 3-digit numbers such that their sum gives a 4-digit number. Addition must not involve carryover. + 3-digit number 3-digit number 4-digit number

To solve this problem, we will focus on two different tasks involving 3-digit numbers. Let's tackle each task step-by-step:
Task 1: Finding two 3-digit numbers that add up to a 3-digit number with carryover

We need to choose two 3-digit numbers such that when we add them, there is at least one carryover involved (like when the sum of digits in a place value exceeds 9).
An example is adding 457 and 368:
Units place: 7 + 8 = 15 (Here, '5' is placed in the units place, and '1' is carried over to the tens place)
Tens place: 5 + 6 + 1 (carry) = 12 (Here, '2' is placed in the tens place, and '1' is carried over to the hundreds place)
Hundreds place: 4 + 3 + 1 (carry) = 8


The final sum is 825, which satisfies the condition of having a carryover and is also a 3-digit number.

Task 2: Finding two 3-digit numbers whose sum is a 4-digit number without carryover

To find such numbers, one easy way is to choose numbers like 500 and 500.
Adding them:
Units place: 0 + 0 = 0
Tens place: 0 + 0 = 0
Hundreds place: 5 + 5 = 10 (Here, '0' is placed in the hundreds place, and the '1' is carried over to create a new thousand place digit)


The sum is 1000, which is a 4-digit number, and the addition did not involve a carryover from tens or units places.

Both examples fulfill the requirements of the problem, showing the process of choosing numbers carefully to meet specific conditions.

Answered by OliviaMariThompson | 2025-07-22